x^2+3x-629=0

Solution for x^2+3x-629=0 equation:

x^2+3x-629=0

a = 1; b = 3; c = -629;
Δ = b2-4ac
Δ = 32-4·1·(-629)
Δ = 2525
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2525}=\sqrt{25*101}=\sqrt{25}*\sqrt{101}=5\sqrt{101}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-5\sqrt{101}}{2*1}=\frac{-3-5\sqrt{101}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+5\sqrt{101}}{2*1}=\frac{-3+5\sqrt{101}}{2}
$